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प्रश्न
The mid-point of the line joining (−a, 2b) and (−3a, −4b) is
पर्याय
(2a, 3b)
(−2a, −b)
(2a, b)
(−2a, −3b)
उत्तर
(−2a, −b)
Explanation;
Hint:
Mid−points of line = `((x_1 + x_2)/2, (y_1 + y_2)/2)`
= `((-"a" - 3"a")/2, (2"b" - 4"b")/2)`
= `((-4"a")/2, (-2"b")/2)`
= (−2a, −b)
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Find the centroid of a triangle whose vertices are (3, -5), (-7, 4) and ( 10, -2).
P , Q and R are collinear points such that PQ = QR . IF the coordinates of P , Q and R are (-5 , x) , (y , 7) , (1 , -3) respectively, find the values of x and y.
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(−2, 3) and (−6, −5)
Find the mid-point of the line segment joining the points
(8, −2) and (−8, 0)
The points A(−3, 6), B(0, 7) and C(1, 9) are the mid-points of the sides DE, EF and FD of a triangle DEF. Show that the quadrilateral ABCD is a parallelogram.
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Point P is the centre of the circle and AB is a diameter. Find the coordinates of points B if coordinates of point A and P are (2, – 3) and (– 2, 0) respectively.
Given: A`square` and P`square`. Let B (x, y)
The centre of the circle is the midpoint of the diameter.
∴ Mid point formula,
`square = (square + x)/square`
⇒ `square = square` + x
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Hence coordinates of B is (– 6, 3).
