Advertisements
Advertisements
Question
The mid-point of the line joining (−a, 2b) and (−3a, −4b) is
Options
(2a, 3b)
(−2a, −b)
(2a, b)
(−2a, −3b)
Solution
(−2a, −b)
Explanation;
Hint:
Mid−points of line = `((x_1 + x_2)/2, (y_1 + y_2)/2)`
= `((-"a" - 3"a")/2, (2"b" - 4"b")/2)`
= `((-4"a")/2, (-2"b")/2)`
= (−2a, −b)
APPEARS IN
RELATED QUESTIONS
Point P is the centre of the circle and AB is a diameter . Find the coordinates of point B if coordinates of point A and P are (2, –3) and (–2, 0) respectively.
If (-3, 2), (1, -2) and (5, 6) are the midpoints of the sides of a triangle, find the coordinates of the vertices of the triangle.
The mid-point of the line segment joining A (- 2 , 0) and B (x , y) is P (6 , 3). Find the coordinates of B.
A( 4, 2), B(-2, -6) and C(l, 1) are the vertices of triangle ABC. Find its centroid and the length of the median through C.
The coordinates of the centroid I of triangle PQR are (2, 5). If Q = (-6, 5) and R = (7, 8). Calculate the coordinates of vertex P.
The coordinates of the end points of the diameter of a circle are (3, 1) and (7, 11). Find the coordinates of the centre of the circle.
Find the mid-point of the line segment joining the points
(−2, 3) and (−6, −5)
The centre of a circle is (−4, 2). If one end of the diameter of the circle is (−3, 7) then find the other end
The points A(−3, 6), B(0, 7) and C(1, 9) are the mid-points of the sides DE, EF and FD of a triangle DEF. Show that the quadrilateral ABCD is a parallelogram.
Find the coordinates of midpoint of segment joining (22, 20) and (0, 16)
