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Point P is the Centre of the Circle and Ab is a Diameter . Find the Coordinates of Point B If Coordinates of Point a and P Are (2, –3) and (–2, 0) Respectively. - Geometry Mathematics 2

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Question

Point P is the centre of the circle and AB is a diameter . Find the coordinates of point B if coordinates of point A and P are (2, –3) and (–2, 0) respectively.

Solution

Centre = P(–2, 0)
Diameter has A(2, –3) on one end and B(x, y) on the other. 
The centre point P divides AB in two equal parts. 
So, using the midpoint formula, 

\[- 2 = \frac{2 + x}{2}\]

\[ \Rightarrow - 4 = 2 + x\]

\[ \Rightarrow x = - 6\]

\[\text { And }\]

\[0 = \frac{- 3 + y}{2}\]

\[ \Rightarrow 0 = - 3 + y\]

\[ \Rightarrow y = 3\]

\[\left( x, y \right) = \left( - 6, 3 \right)\]

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The Mid-point of a Line Segment (Mid-point Formula)
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Chapter 5: Co-ordinate Geometry - Practice Set 5.2 [Page 115]

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Balbharati Geometry (Mathematics 2) [English] 10 Standard SSC Maharashtra State Board
Chapter 5 Co-ordinate Geometry
Practice Set 5.2 | Q 4 | Page 115

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