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Question
Find the coordinates of point P where P is the midpoint of a line segment AB with A(–4, 2) and B(6, 2).
Solution :
Suppose, (–4, 2) = (x1, y1) and (6, 2) = (x2, y2) and co-ordinates of P are (x, y).
∴ According to the midpoint theorem,
x = `(x_1 + x_2)/2 = (square + 6)/2 = square/2 = square`
y = `(y_1 + y_2)/2 = (2 + square)/2 = 4/2 = square`
∴ Co-ordinates of midpoint P are `square`.
Solution
Suppose, (–4, 2) = (x1, y1) and (6, 2) = (x2, y2) and coordinates of P are (x, y).
∴ According to the midpoint theorem,
x = `(x_1 + x_2)/2 = (bb(-4) + 6)/2 = bb2/2` = 1
y = `(y_1 + y_2)/2 = (2 + bb2)/2 = 4/2` = 2
∴ The coordinates of midpoint P are (1, 2).
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