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Question
The centre of a circle is (a+2, a-1). Find the value of a, given that the circle passes through the points (2, -2) and (8, -2).
Solution
OA = OB [radii of same circle]
∴ OA2 = OB2
(a + 2 - 2)2 + (a - 1 + 2)2 = (a + 2 - 8)2 + (a - 1 + 2)2
a2 + (a + 1)2 = (a - 6)2 + (a + 1)2
a2 = a2 + 36 - 12a
12 a = 36
a = 3
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