Advertisements
Advertisements
प्रश्न
The number x is 2 more than the number y. If the sum of the squares of x and y is 34, then find the product of x and y.
उत्तर
Given x is 2 more than y, so x = y + 2
Sum of squares of x and y is 34, so x2 + y2 = 34.
Replace x = y + 2 in the above equation and solve for y.
We get (y + 2)2 + y2 = 34
2y2 + 4y - 30 = 0
y2 + 2y - 15 = 0
(y + 5)(y - 3) = 0
So y = -5 or 3
For y = -5, x =-3
For y = 3, x = 5
Product of x and y is 15 in both cases.
APPEARS IN
संबंधित प्रश्न
Factorise the following:
27 – 125a3 – 135a + 225a2
Simplify the following products:
`(1/2a - 3b)(1/2a + 3b)(1/4a^2 + 9b^2)`
Write the expanded form:
`(-3x + y + z)^2`
Find the following product:
If x = −2 and y = 1, by using an identity find the value of the following
Evaluate : (4a +3b)2 - (4a - 3b)2 + 48ab.
Evaluate the following without multiplying:
(95)2
Simplify:
`("a" - 1/"a")^2 + ("a" + 1/"a")^2`
Factorise the following:
`(2x + 1/3)^2 - (x - 1/2)^2`
Expand the following:
`(1/x + y/3)^3`