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प्रश्न
"The outward electric flux due to charge +Q is independent of the shape and size of the surface which encloses is." Give two reasons to justify this statement.
उत्तर
The outward electric flux due to the charge enclosed inside a surface is the number of electric field lines coming out of the surface.
The outward electric flux due to charge +Q is independent of the shape and size of the surface, which encloses it because of the following reasons:
(i) Number of electric field lines coming out from a closed surface enclosing the charge depends on the charge enclosed by the surface, which remains constant with shape and size of the conductor.
(ii) Number of electric field lines coming out from a closed surface enclosing the charge is independent of the position of the charge inside the closed surface.
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संबंधित प्रश्न
Consider a uniform electric field E = 3 × 103 `bbhat i` N/C.
- What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane?
- What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?
Given a uniform electric field \[\vec{E} = 2 \times {10}^3 \ \hat{i}\] N/C, find the flux of this field through a square of side 20 cm, whose plane is parallel to the y−z plane. What would be the flux through the same square, if the plane makes an angle of 30° with the x−axis ?
Two charges of magnitudes −3Q and + 2Q are located at points (a, 0) and (4a, 0) respectively. What is the electric flux due to these charges through a sphere of radius ‘5a’ with its centre at the origin?
A thin straight infinitely long conducting wire having charge density λ is enclosed by a cylindrical surface of radius r and length l, its axis coinciding with the length of the wire. Find the expression for the electric flux through the surface of the cylinder.
A circular ring of radius r made of a non-conducting material is placed with its axis parallel to a uniform electric field. The ring is rotated about a diameter through 180°. Does the flux of the electric field change? If yes, does it decrease or increase?
Mark the correct options:
If the flux of the electric field through a closed surface is zero,
(a) the electric field must be zero everywhere on the surface
(b) the electric field may be zero everywhere on the surface
(c) the charge inside the surface must be zero
(d) the charge in the vicinity of the surface must be zero
Electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10 cm surrounding the total charge is 25 V m. The flux over a concentric sphere of radius 20 cm will be _____________ .
A hollow sphere of radius R has a point charge q at its centre. Electric flux emanating from the sphere is X. How will the electric flux change, if at all, when charge q is replaced by an electric dipole?
