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प्रश्न
The point (−3, 2) lies on the line ax + 3y + 6 = 0, calculate the value of a.
उत्तर
Given, the point (−3, 2) lies on the line ax + 3y + 6 = 0.
Substituting x = −3 and y = 2 in the given equation, we have:
a(−3) + 3(2) + 6 = 0
−3a + 12 = 0
3a = 12
a = 4
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