मराठी

The Points A(2, 0), B(9, 1) C(11, 6) and D(4, 4) Are the Vertices of a Quadrilateral Abcd. Determine Whether Abcd is a Rhombus Or Not. - Mathematics

Advertisements
Advertisements

प्रश्न

The points A(2, 0), B(9, 1) C(11, 6) and D(4, 4) are the vertices of a quadrilateral ABCD. Determine whether ABCD is a rhombus or not.

उत्तर

Let A (2, 0); B (9, 1); C (11, 6) and D `(4, 4) be the vertices of a quadrilateral. We have to check if the quadrilateral ABCD is a rhombus or not.

So we should find the lengths of sides of quadrilateral ABCD.

`AB = sqrt((9-2)^2 + (1 - 0)^2)`

`= sqrt(49 + 1)`

`= sqrt50`

`BC= sqrt((11 - 9)^2 + (6 -1)^2)``

`= sqrt(4 + 25)`

`= sqrt29`

`CD = sqrt((11 - 4)^2 + (6 - 4)^2)`

`= sqrt(49 + 4)`

`= sqrt53`

`AD = sqrt((4- 5)^2 + (4 - 0)^2)`

`= sqrt(4 + 16)`

`= sqrty(20)`

All the sides of quadrilateral are unequal. Hence ABCD is not a rhombus.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Co-Ordinate Geometry - Exercise 6.3 [पृष्ठ २९]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
पाठ 6 Co-Ordinate Geometry
Exercise 6.3 | Q 24 | पृष्ठ २९

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Prove that the points (3, 0), (6, 4) and (-1, 3) are the vertices of a right-angled isosceles triangle.


Prove that (4, 3), (6, 4) (5, 6) and (3, 5)  are the angular points of a square.


Show that the points A (1, 0), B (5, 3), C (2, 7) and D (−2, 4) are the vertices of a parallelogram.


If the poin A(0,2)  is equidistant form the points B (3, p) and  C (p ,5) find the value of p. Also, find the length of AB.


If the point A(0,2) is equidistant from the points B(3,p) and C(p, 5), find p.


In what ratio does the point C (4,5) divides the join of A (2,3)  and B (7,8) ?


Find the possible pairs of coordinates of the fourth vertex D of the parallelogram, if three of its vertices are A(5, 6), B(1, –2) and C(3, –2).


If `P(a/2,4)`is the mid-point of the line-segment joining the points A (−6, 5) and B(−2, 3), then the value of a is


The abscissa and ordinate of the origin are


The area of the triangle formed by the points A(2,0) B(6,0)  and C(4,6) is


If A(−3, 5), B(−2, −7), C(1, −8) and D(6, 3) are the vertices of a quadrilateral ABCD, find its area.


If three points (x1, y1) (x2, y2), (x3, y3) lie on the same line, prove that  \[\frac{y_2 - y_3}{x_2 x_3} + \frac{y_3 - y_1}{x_3 x_1} + \frac{y_1 - y_2}{x_1 x_2} = 0\]

 


If the centroid of the triangle formed by points P (a, b), Q(b, c) and R (c, a) is at the origin, what is the value of a + b + c?


If A (2, 2), B (−4, −4) and C (5, −8) are the vertices of a triangle, than the length of the median through vertex C is


If (−2, 1) is the centroid of the triangle having its vertices at (x , 0) (5, −2),  (−8, y), then xy satisfy the relation


The coordinates of the fourth vertex of the rectangle formed by the points (0, 0), (2, 0), (0, 3) are


Find the coordinates of point A, where AB is a diameter of the circle with centre (–2, 2) and B is the point with coordinates (3, 4).


Which of the points P(0, 3), Q(1, 0), R(0, –1), S(–5, 0), T(1, 2) do not lie on the x-axis?


If the points P(1, 2), Q(0, 0) and R(x, y) are collinear, then find the relation between x and y.

Given points are P(1, 2), Q(0, 0) and R(x, y).

The given points are collinear, so the area of the triangle formed by them is `square`.

∴ `1/2 |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)| = square`

`1/2 |1(square) + 0(square) + x(square)| = square`

`square + square + square` = 0

`square + square` = 0

`square = square`

Hence, the relation between x and y is `square`.


The coordinates of two points are P(4, 5) and Q(–1, 6). Find the difference between their abscissas.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×