Advertisements
Advertisements
प्रश्न
The side AB of an equilateral triangle ABC is parallel to the x-axis. Find the slopes of all its sides.
उत्तर
We know that the slope of any line parallel to x-axis is 0.
Therefore, slope of AB = 0
Since, ABC is an equilateral triangle, ∠A = 60°
Slope of AC = tan 60° = `sqrt(3)`
Slope of BC = –tan 60° = `-sqrt(3)`
APPEARS IN
संबंधित प्रश्न
The slope of a line joining P(6, k) and Q(1 – 3k, 3) is `1/2`. Find:
- k.
- mid-point of PQ, using the value of ‘k’ found in (i).
The line through A(–2, 3) and B(4, b) is perpendicular to the line 2x – 4y = 5. Find the value of b.
A and B are two points on the x-axis and y-axis respectively. P (2, −3) is the midpoint of AB. Find the:
(1) coordinates of A and B
(2) slope of line AB.
(3) an equation of line AB.
If the lines y = 3x + 7 and 2y + px = 3 are perpendicular to each other, find the value of p.
Find k, if PQ || RS and P(2, 4), Q (3, 6), R(3, 1), S(5, k).
Fill in the blank using correct alternative.
Out of the following, point ........ lies to the right of the origin on X– axis.
Find the slope of the line passing through the points A(4,7) and B(2,3).
Find the value, of k, if the line represented by kx – 5y + 4 = 0 and 4x – 2y + 5 = 0 are perpendicular to each other.
Find the image of a point (-1, 2) in the line joining (2, 1) and (- 3, 2).
