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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

The slope of the tangent to the curve x = 1t, y = t-1t, at t = 2 is ______ - Mathematics and Statistics

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प्रश्न

The slope of the tangent to the curve x = `1/"t"`, y = `"t" - 1/"t"`, at t = 2 is ______

रिकाम्या जागा भरा

उत्तर

– 5 

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पाठ 1.4: Applications of Derivatives - Q.2

संबंधित प्रश्‍न

Find the derivative of the following function from first principle.

(x – 1) (x – 2)


Find the derivative of the following function from first principle.

`(x+1)/(x -1)`


Find the derivative of the following function from first principle:

−x


Find the derivative of the following function from first principle:

(–x)–1


Find the derivative of the following function from first principle: 

`cos (x - pi/8)`


Find the equation of tangent and normal to the curve at the given points on it.

2x2 + 3y2 = 5 at (1, 1)


Find the equation of tangent and normal to the curve at the given points on it.

x2 + y2 + xy = 3 at (1, 1)


Find the equations of tangent and normal to the curve y = x2 + 5 where the tangent is parallel to the line 4x − y + 1 = 0.


Find the equations of tangent and normal to the curve y = 3x2 - 3x - 5 where the tangent is parallel to the line 3x − y + 1 = 0.


Choose the correct alternative.

The equation of tangent to the curve y = x2 + 4x + 1 at (-1, -2) is 


Choose the correct alternative.

The equation of tangent to the curve x2 + y2 = 5 where the tangent is parallel to the line 2x – y + 1 = 0 are


Choose the correct alternative.

If elasticity of demand η = 1, then demand is


Choose the correct alternative.

If f(x) = 3x3 - 9x2 - 27x + 15 then


Fill in the blank:

The slope of tangent at any point (a, b) is called as _______.


State whether the following statement is True or False:

The equation of tangent to the curve y = 4xex at `(-1, (- 4)/"e")` is ye + 4 = 0


Find the equation of tangent and normal to the following curve.

xy = c2 at `("ct", "c"/"t")` where t is parameter.


Choose the correct alternative:

Slope of the normal to the curve 2x2 + 3y2 = 5 at the point (1, 1) on it is 


y = ae2x + be-3x is a solution of D.E. `(d^2y)/dx^2 + dy/dx + by = 0`


Find the equations of tangent and normal to the curve y = 6 - x2 where the normal is parallel to the line x - 4y + 3 = 0


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