Advertisements
Advertisements
प्रश्न
Use the adjoining figure to find: (i) ∠BOD (ii) ∠AOC
उत्तर
∠AOD = 72°
∠BOC = 64°
But sum of angles on the same side of a line = 180°
∴ ∠AOD + ∠COD + ∠BOC = 180°
72° + ∠COD + 64° = 180°
∠COD = 180° - (72° + 64°)
= 180° - 136° = 44°
(i) Now ∠BOD = ∠BOC + ∠COD
= 64° + 44° = 108°
(ii) ∠AOC = ∠AOD + ∠COD
= 72° + 44° = 116°
APPEARS IN
संबंधित प्रश्न
In the given figure, PQR is a straight line. Find x. Then complete the following:
(i) ∠AQB = _______
(ii) ∠BQP = _______
(iii) ∠AQR = _______
In the given figure, lines AB and CD intersect at point O.
(i) Find the value of ∠a.
(ii) Name all the pairs of vertically opposite angles.
(iii) Name all the pairs of adjacent angles.
(iv) Name all the reflex angles formed and write the measure of each.
Write the complement angle of: 45°
Write the complement angle of: 20° + y°
Write the supplement angle of: (x – 30)°
Write the complement angle of: `1/2` of 60°
Write the complement angle of: `1/5` of 160°
For an angle x°, find:
(i) the complementary angle
(ii) the supplementary angle
(iii) the value of x° if its supplementary angle is three times its complementary angle.
Find the angle formed by the arms of a clock at 3 O’clock.
Find the angle that is three times its complementary angle.