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प्रश्न
With the help of the flow chart given below solve the equation \[x^2 + 2\sqrt{3}x + 3 = 0\] using the formula.
उत्तर
Comparing `x^2 + 2sqrt3x + 3 = 0` with ax2 + bx + c = 0
we get a = 1, b = 2`sqrt3` and c = 3
b2 - 4ac = `(2sqrt3)^2- 4xx1xx3`
= 12 - 12
= 0
Formula to solve a quadratic equation will be
x = `(- b±sqrt(b^2 - 4ac))/(2a)`
⇒ x = `(-2sqrt3±sqrt(0))/(2xx1)`
= `(-2sqrt3)/2`
= `-sqrt3`
Thus, `x = -sqrt3, -sqrt3`
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