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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Wo Roots of Quadratic Equations Are Given ; Frame the Equation. 1 − 3 √ 5 and 1 + 3 √ 5 - Algebra

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प्रश्न

Two roots of quadratic equation is given ; frame the equation.

\[1 - 3\sqrt{5} \text{ and } 1 + 3\sqrt{5}\] 

बेरीज

उत्तर

\[1 - 3\sqrt{5} \text{ and } 1 + 3\sqrt{5}\]

Sum of roots = \[1 - 3\sqrt{5} + 1 + 3\sqrt{5} = 2\]

Product of roots = \[\left( 1 - 3\sqrt{5} \right)\left( 1 + 3\sqrt{5} \right) = 1 - 45 = - 44\]

The general form of the quadratic equation is \[x^2 - \left( \text{ Sum of roots } \right)x + \text{ product of roots } = 0\]

So, the quadratic equation will be  \[x^2 - 2x - 44 = 0\]

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पाठ 2: Quadratic Equations - Problem Set 2 [पृष्ठ ५४]

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बालभारती Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board
पाठ 2 Quadratic Equations
Problem Set 2 | Q 5.2 | पृष्ठ ५४

संबंधित प्रश्‍न

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If 2 and 5 are the roots of the quadratic equation, then complete the following activity to form quadratic equation:

Activity:

Let α = 2 and β = 5 are the roots of the quadratic equation.

Then quadratic equation is:

x2 − (α + β)x + αβ = 0

∴ `x^2 - (2 + square)x + square xx 5 = 0`

∴ `x^2 - square x + square = 0`


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