Advertisements
Advertisements
Question
A bag contains 100 identical marble stones which are numbered 1 to 100. If one stone is drawn at random from the bag, find the probability that it bears a number divisible by 5.
Solution
Total number of possible outcomes = 100
Numbers which are divisible by 5 = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100
Number of favorable outcomes = 20
P(number divisible by 5) = `20/100 = 1/5`
APPEARS IN
RELATED QUESTIONS
A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is not red?
Two customers are visiting a particular shop in the same week (Monday to Saturday). Each is equally likely to visit the shop on any one day as on another. What is the probability that both will visit the shop on different days?
A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is Not black
Fill in blank:
Probability of an event A + Probability of event ‘not A’ ...........
Write the probability of a sure event.
Two dice are thrown simultaneously. What is the probability that:
- 4 will not come up either time?
- 4 will come up at least once?
How many possibilities is the following?
Vanita knows the following sites in Maharashtra. She is planning to visit one of them in her summer vacation.
Ajintha, Mahabaleshwar, Lonar Sarovar, Tadoba wild life sanctuary, Amboli, Raigad, Matheran, Anandavan.
Two dice are thrown simultaneously. What is the probability that the sum of the numbers appearing on the dice is a prime number?
Following experiment have equally likely outcomes? Explain.
A player attempts to shoot a basketball. She/he shoots or misses the shot.
The table given below shows the months of birth of 36 students of a class:
Month of birth |
Jan. | Feb. | Mar. | Apr. | May | June | July | Aug. | Sept. | Oct. | Nov. | Dec. |
No. of students |
4 | 3 | 5 | 0 | 1 | 6 | 1 | 3 | 4 | 3 | 4 | 2 |
A student is choosen at random. Fill in the boxes.
Total number of students = `square`
Let E be the event that the selected student is born in June.
Then,
Number of times event E occurs = `square`
So, P (selected student is born in June)
P(E) = `"Number of students born in June"/square`
= `square/square`
= `square`