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Question
A bag contains 4 white balls, 5 red balls, 2 black balls and 4 green balls. A ball is drawn at random from the bag. Find the probability that it is neither red nor green.
Solution
Total number of balls = 15
Number of balls which are neither red nor green = 4 + 2 = 6
∴ P(getting a ball which is neither red nor green) = `"Number of favourable outcome"/"Number of all possible outcomes" = 6/15 = 2/5`
= `6/15 = 2/5`
Thus, the probability of getting a ball which is neither red nor green is
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