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Question
A cylinderical container with a diameter of base 42 cm contains sufficient water to submerge a rectangular solid of iron with dimesions 22 cm × 14 cm × 10.5 cm. Find the rise in level of the water when the solid is submerged.
Solution
Given:
cylindrical container
D = 42 cm
r = `42/2 = 21` cm
H = ?
Rectangular solid
l = 22
b = 14
h = 10.5 cm
The volume of container = The volume of solid
πr2H = l × b × h
`22/7 xx 21 xx 21 xx "H" = 22 xx 14 xx 10.5`
`"H" = (22 xx 14 xx 10.5 xx 7)/(22 xx 21 xx 21)`
= `(2 xx 10.5)/9`
= `21/9`
= `7/3`
H = `2 1/3` or 2.33 cm
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