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Question
A cylindrical container with internal radius of its base 10 cm, contains water up to a height of 7 cm. Find the area of the wet surface of the cylinder.
Solution
Internal radius of the cylinderical container = 10 cm
Height of water = 7 cm
Therefore, surface area of the wet surface = 2πrh + πr2
= πr(2h + r)
= `22/7 xx 10 xx (2 xx 7 + 10)`
= `220/7 xx 24`
= 754.29 cm2
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