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Question
A cylindrical road roller made of iron is 1 m long, Its internal diameter is 54 cm and the thickness of the iron sheet used in making the roller is 9 cm. Find the mass of the roller, if 1 cm3 of iron has 7.8 gm mass. (Use π = 3.14)
Solution
We have to find the mass of the roller.
Radius of inner cylinder(r1) = 27 cm
Radius of outer cylinder
(r2) = (27 + 9) cm
= 36 cm
Length of the cylinder(h) = 100 cm
So, volume of iron,
`=rh(r_2^2-r_1^2)`
=(3.14)(100)(1296-729)
=178038 cm3
It is given that, 1 cm3 of iron has a mass of 7.8 gm.
So the mass of iron used,
= (178038)(7.8) gm
= 1388696.4 gm
= 1388.7 kg
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