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Question
A die is rolled, then the probability that a number 1 or 6 may appear is
Options
2/3
5/6
1/3
1/2
Solution
1/3
Total number of sample space, S = {1, 2, 3, 4, 5, 6}
∴ n(S) = 6
Let A be the event of getting the number 1 or 6.
A = {1, 6}
i.e. n(A) = 2
Hence, required probability = \[\frac{n\left( A \right)}{n\left( S \right)} = \frac{2}{6} = \frac{1}{3}\]
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