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Question
A bag contains 6 red, 4 white and 8 blue balls. If three balls are drawn at random, find the probability that two are blue and one is red
Solution
Out of 18 balls, three balls can be drawn in 18C3 ways.
∴ Total number of elementary events = 18C3 = 816
Out of eight blue balls, two blue balls can be drawn in 8C2 ways.
Out of six red balls, one red ball can be drawn in 6C1 ways .
Therefore, two blue and one red balls can be drawn in 8C2 × 6C1 = 28 × 6 = 168 ways
∴ Favourable number of ways = 168
Hence, required probability =
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