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A Bag Contains 6 Red, 4 White and 8 Blue Balls. If Three Balls Are Drawn at Random, Find the Probability That:(Ii) Two Are Blue and One is Red - Mathematics

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प्रश्न

A bag contains 6 red, 4 white and 8 blue balls. If three balls are drawn at random, find the probability that two are blue and one is red

उत्तर

Out of 18 balls, three balls can be drawn in 18C3 ways.
∴ Total number of elementary events = 18C3 = 816

Out of eight blue balls, two blue balls can be drawn in 8C2 ways.
Out of six red balls, one red ball can be drawn  in 6C1 ways .
Therefore, two blue and one red balls can be drawn in 8C2 × 6C1 = 28 × 6 = 168 ways
 ∴ Favourable number of ways = 168
Hence, required probability =

\[\frac{168}{816} = \frac{7}{34}\]

 

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अध्याय 33: Probability - Exercise 33.3 [पृष्ठ ४६]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 33 Probability
Exercise 33.3 | Q 16.2 | पृष्ठ ४६

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