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Question
Three dice are thrown simultaneously. What is the probability of getting 15 as the sum?
Solution
If three dices are thrown simultaneously, then the number of all the possible outcomes are 63 = 216.
∴ Total number of possible outcome = n(S) = 216
Let A be the event of getting a sum of 15 when three dices are thrown simultaneously.
The favourable outcomes are as follows:
A = {(3,6 , 6), (4, 6, 5), (5, 6, 4), (6, 6, 3), (6, 3, 6), (6, 4, 5), (6, 5, 4), (4, 5, 6), (5, 5, 5), (5, 4, 6)}
i.e. number of favourable outcomes = n(A) = 10
Hence, required probability = P (getting a sum of 15) = \[\frac{10}{216}\]
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