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Question
A dinner plate is in the form of circle. A circular region encloses a beautiful design as shown in the given figure. The inner circumference is 352 mm and outer is 396 mm. Find the width of circular design.
Solution
Let the radius of inner and outer circle be rand R, respectively.
Given, inner circumference = 352 mm
⇒ 2πr = 352 ......[∵ Circumference = 2πr]
⇒ `2 xx 22/7 xx r` = 352
⇒ r = `(352 xx 7)/(2 xx 22) = 2464/44` = 56 mm
and outer circumference = 396 mm .....[Given]
⇒ 2πr = 396
⇒ `2 xx 22/7 xx R` = 396
⇒ R = `(396 xx 7)/(2 xx 22)` = 63 mm
∴ Width of circular design = R – r = 63 – 56 = 7 mm
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