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A Long Horizontal Wire P Carries a Current of 50a. It is Rigidly Fixed. Another Wire Q is Placed Directly Above and Parallel to P, as Shown in Figure 1 Below. the Weight per Unit Length of the Wire Q is 0.025 Nm-1 and It Carries a Current of 25a. Find the Distance 'R' of the Wire Q from the Wire P So that the Wire Q Remains at Rest - Physics (Theory)

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Question

A long horizontal wire P carries a current of 50A. It is rigidly fixed. Another wire Q is placed directly above and parallel to P, as shown in Figure 1 below. The weight per unit length of the wire Q is 0.025 Nm-1 and it carries a current of 25A. Find the distance 'r' of the wire Q from the wire P so that the wire Q remains at rest

Solution

`F/l  = mu_0/(4pi)  (2I_1I_2)/r`

`0.025 = 10^(-7) xx (2xx50xx25)/r`

r = 0.01 m

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Force on a Moving Charge in Uniform Magnetic and Electric Fields
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2017-2018 (March) Set 1

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