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A Rangoli has been drawn on a flor of a house. ABCD and PQRS both are in the shape of a rhombus. Find the radius of semicircle drawn on each side of rhombus ABCD. - Mathematics

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Question

A Rangoli has been drawn on a flor of a house. ABCD and PQRS both are in the shape of a rhombus. Find the radius of semicircle drawn on each side of rhombus ABCD.

Sum

Solution

In rhombus ABCD,

AO = OP + PA

= 2 + 2

= 4 units

And OB = OQ + QB

= 2 + 1

= 3 units

We know that, diagonals of rhombus bisect each other at 90°.

Now, In ΔOAB,

(AB)2 = (OA)2 + (OB)2  ...[By Pythagoras theorem]

⇒ (AB)2 = (4)2 + (3)2

⇒ (AB)2 = 16 + 9

⇒ (AB)2 = 25

⇒ AB = `sqrt(25)`

⇒ AB = 5 units

Since, AB is diameter of semi-circle.

∴ Radius = `"Diameter"/2`

= `(AB)/2`

= `5/2`

= 2.5 units

Hence, radius of the semi-circle is 2.5 units.

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Chapter 5: Understanding Quadrilaterals and Practical Geometry - Exercise [Page 159]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 5 Understanding Quadrilaterals and Practical Geometry
Exercise | Q 158 | Page 159

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