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Questions
A reaction takes place in two steps:
- \[\ce{NO_{(g)} + Cl2_{(g)} -> NOCl2_{(g)}}\]
- \[\ce{NOCl2_{(g)} + NO_{(g)} -> 2NOCl_{(g)}}\]
- Write the overall reaction.
- Identify the reaction intermediate.
- What is the molecularity of each step?
A reaction takes place in two steps:
- \[\ce{NO_{(g)} + Cl2_{(g)} -> NOCl2_{(g)}}\]
- \[\ce{NOCl2_{(g)} + NO_{(g)} -> 2NOCl_{(g)}}\]
- Write the overall reaction.
- Identify the reaction intermediate.
Solution
- Overall reaction: \[\ce{2NO_{(g)} + Cl_{2(g)} -> 2NOCl_{(g)}}\]
- Since NOCl2 is formed in the first step and consumed in the second step, it is the reaction intermediate.
- The molecularity of each step is 2 because two reactants are involved in each of the steps.
Notes
Students should refer to the answer according to their questions.
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