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Question
A sample of gas has a volume of 8.5 dm3 at an unknown temperature. When the sample is submerged in ice water at 0°C, its volume gets reduced to 6.37 dm3. What is its initial temperature?
Solution
V1 = 8.5 dm3
V2 = 6.37 dm3
T1 = ?
T2 = 0°C = 273 K
`"V"_1/"T"_1 = "V"_2/"T"_2`
`"V"_1 xx ("T"_2/"V"_2) = "T"_1`
T1 = `8.5 "dm"^3 xx (273 "K")/(6.37 "dm"^3)`
T1 = 364.28 K
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