Advertisements
Advertisements
Question
A ship is 400m laig and 100m wide. The length of its model is 20 cm. find the surface area of the deck of the model.
Solution
20 cm represents 400 m
1 cm represesnts `400/20` = 20 cm
Width of model = `100/20` = 5 cm
Length of model = 20 cm
Surface area of the deck of the model= 5 cm x 20 cm
= 100 cm2
APPEARS IN
RELATED QUESTIONS
In a triangle ABC, line l || Side BC and line l intersects side AB and AC in points P and Q, respectively. Prove that: `"AP"/"BP"="AQ"/"QC"`
In the given figure, ∠ABC = 90° and BD⊥AC. If AB = 5.7cm, BD = 3.8cm and CD = 5.4cm, find BC.
In the figure, given below, PQR is a right-angle triangle right angled at Q. XY is parallel to QR, PQ = 6 cm, PY = 4 cm and PX : XQ = 1 : 2. Calculate the lengths of PR and QR.
In ΔABC, D and E are the mid-point on AB and AC such that DE || BC.
If AD : BD = 4 : 5 and EC = 2.5cm, find AE.
In ΔABC, BP and CQ are altitudes from B and C on AC and AB respectively. BP and CQ intersect at O. Prove that
(i) PC x OQ = QB x OP
(ii) `"OC"^2/"OB"^2 = ("PC" xx "PO")/("QB" xx "QO")`
Given that ΔABC ∼ ΔPRQ, name the corresponding angles and the corresponding sides.
In the given figure, UB || AT and CU ≡ CB Prove that ΔCUB ~ ΔCAT and hence ΔCAT is isosceles.
In the figure, if ∠FEG ≡ ∠1 then, prove that DG2 = DE.DF
State whether the following triangles are similar or not: If yes, then write the test of similarity.
∠P = 35°, ∠X = 35° and ∠Q = 60°, ∠Y = 60°
In the given figure, if ABCD is a trapezium in which AB || CD || EF, then prove that `(AE)/(ED) = (BF)/(FC)`.
