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Question
ABC is an isosceles triangle right angled at C. Prove that AB2 = 2AC2
Solution
Given that ΔABC is an isosceles triangle.
∴ AC = CB
Applying Pythagoras theorem in ΔABC (i.e., right-angled at point C), we obtain
AC2 + CB2 = AB2
=> AC2+ AC2 = AB2 (AC = CB)
⇒ 2AC2 = AB2
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