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Question
An aeroplane leaves an airport and flies due north at a speed of 1,000 km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1,200 km per hour. How far apart will be the two planes after `1 1/2` hours?
Solution
Distance travelled by the plane flying towards north in `1 1/2 `
Similarly, distance travelled by the plane flying towards west in `1 1/2 `
Let these distances be represented by OA and OB respectively.
Applying Pythagoras theorem,
Distance between these planes after `1 1/2 `
`= (sqrt((1500)^2 + (1800)^2)) `
`= (sqrt5490000)`
Therefore, the distance between these planes will be `300sqrt(61) `
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