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Question
Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops.
Solution
Let CD and AB be the poles of height 11 m and 6 m.
Therefore, CP = 11 − 6 = 5 m
From the figure, it can be observed that AP = 12m
Applying Pythagoras theorem for ΔAPC, we obtain
AP2 + PC2 = AC2
(12 m)2 + (5m)2 = (AC)2
AC2 = (144 + 25)m2 = 169 m2
AC = 13m
Therefore, the distance between their tops is 13 m.
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