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An area is paved with square tiles of a certain size and the number required is 128. If the tiles had been 2 cm smaller each way, 200 tiles would have been needed to pave the same area - Mathematics

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Question

An area is paved with square tiles of a certain size and the number required is 128. If the tiles had been 2 cm smaller each way, 200 tiles would have been needed to pave the same area. Find the size of the larger tiles.

Sum

Solution

Let the size of the larger tiles be x cm.

Area of larger tiles = x2 cm2

Number of larger tiles required to pave an area is 128.

So, the area needed to be paved = 128x2 cm2  ...(1)

Size of smaller tiles = (x – 2) cm

Area of smaller tiles = (x – 2)2 cm2

Number of larger tiles required to pave an area is 200.

So, the area needed to be paved = 200(x – 2)2 cm2  ...(2)

Therefore, from (1) and (2), we have:

128x2 = 200(x – 2)2

128x2 = 200x2 + 800 – 800x

72x2 – 800x + 800 = 0

9x2 – 100x + 100 = 0

9x2 – 90x – 10x + 100 = 0

9x(x – 10) – 10(x – 10) = 0

(x – 10)(9x – 10) = 0

`x = 10,10/9`

If `x = 10/9`,

Then `x - 2 = 10/9 - 2`

= `(10 - 18)/9`

= `(-8)/9`

Which is not possible.

Hence, the size of the larger tiles is 10 cm.

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Problems Based on Geometrical Figures
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Chapter 6: Solving (simple) Problems (Based on Quadratic Equations) - Exercise 6 (B) [Page 71]

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Selina Mathematics [English] Class 10 ICSE
Chapter 6 Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6 (B) | Q 10 | Page 71
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