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Question
Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.
(R = 0.083 bar dm3 K–1 mol–1).
Solution
Given,
n = 4.0 mol
V = 5 dm3
p = 3.32 bar
R = 0.083 bar dm3 K–1 mol–1
The temperature (T) can be calculated using the ideal gas equation as:
pV = nRT
`=> "T" = ("pV")/("nR")`
`= (3.32xx 5)/(4xx0.083)`
= 50 K
Hence, the required temperature is 50 K.
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