Advertisements
Advertisements
Question
Compare the given quadratic equation to the general form and write values of a,b, c.
2m2 = 5m – 5
Solution
2m2 = 5m – 5
\[\Rightarrow 2 m^2 - 5m + 5 = 0\]
General form of the quadratic equation is \[a x^2 + bx + c = 0\] Comparing 2m2 = 5m – 5 with the general form we have a = 2, b = \[-5\] and c = 5.
APPEARS IN
RELATED QUESTIONS
Solve using formula.
x2 – 3x – 2 = 0
Solve using formula.
5m2 – 4m – 2 = 0
Solve using formula.
y2 + `1/3`y = 2.
The roots of the following quadratic equation is real and equal, find k.
kx (x – 2) + 6 = 0
Find the value of discriminant of the following equation.
5m2 - m = 0
Find the value of discriminant of the following equation.
\[\sqrt{5} x^2 - x - \sqrt{5} = 0\]
One of the roots of quadratic equation \[2 x^2 + kx - 2 = 0\] is –2. find k.
Two roots of quadratic equation is given ; frame the equation.
10 and –10
Two roots of quadratic equation is given ; frame the equation.
\[1 - 3\sqrt{5} \text{ and } 1 + 3\sqrt{5}\]
Determine the nature of root of the quadratic equation.
\[3 x^2 - 5x + 7 = 0\]
Determine the nature of root of the quadratic equation.
m2 - 2m + 1 = 0
Find m if (m – 12) x2 + 2(m – 12) x + 2 = 0 has real and equal roots.
The difference between squares of two numbers is 120. The square of smaller number is twice the greater number. Find the numbers.
If 2 and 5 are the roots of the quadratic equation, then complete the following activity to form quadratic equation:
Activity:
Let α = 2 and β = 5 are the roots of the quadratic equation.
Then quadratic equation is:
x2 − (α + β)x + αβ = 0
∴ `x^2 - (2 + square)x + square xx 5 = 0`
∴ `x^2 - square x + square = 0`