Question

Consider the change in the oxidation state of Bromine corresponding to different emf values as shown in the diagram below:

\[\ce{BrO^-_4 ->[1.82 V] BrO^-_3 ->[1.5 V] HBrO ->[1.595 V] Br2 ->[1.0652 V] Br^-}\]

Then the species undergoing disproportionation is

Options

• Br₂

• \[\ce{BrO^-_4}\]

• \[\ce{BrO^-_3}\]

• HBrO

Answer 1

HBrO

Explanation:

(E_cell)_A = – 1.82 + 1.5 = – 0.32 V

(E_cell)_B = – 1.5 + 1.595 = + 0.095 V

(E_cell)_C = 1.595 + 1.0652 = – 0.529 V

∴ The species undergoing disproportionation is HBrO.