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Question
Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.
Solution
Area of ABFE
= `1/2` (AB + EF) × 4 cm2
= `1/2` (24 + 16) × 4 cm2
= `1/2` × 40 × 4 cm2
= 80 cm2
Also, Area of GHDC = Area of ABFE
= 80 cm2
Area of AEGC = `1/2` (EG + AC) × 4cm2
= `1/2 (20 + 28)` × 4cm2
= 96 cm2
Also, Area of AEGC = BFHD = 96 cm2 Area of EFHG
= HG × HF
= 16 × 20 cm2
= 320 cm2
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