Advertisements
Advertisements
Question
Draw ∠ABC of measure 120° and bisect it.
Solution
Steps for construction:-
- Draw BC = 5 cm (any)
- Place the centre of the protractor on B along the base line BC
- Using protractor construct m∠ABC = 120°.
- Draw an arc with centre at B and any fixed radius.
- Mark the points of intersection of the arc with the arms as P and Q.
- Keeping the same radius and with centres P and Q, draw arcs.
- Mark the point of intersection of the arcs as D
- Join BD. BD is the angle bisector of ∠ABC.
APPEARS IN
RELATED QUESTIONS
ΔSHR ~ ΔSVU. In ΔSHR, SH = 4.5 cm, HR = 5.2 cm, SR = 5.8 cm and `"SH"/("SV")=3/5`. Construct ΔSVU.
Draw ∠ABC of measure 105° and bisect it.
Draw `angle ABC` of measure 80° and bisect it
Draw ∠ABC of measures 135°and bisect it.
Ponit M is the mid point of seg AB and AB = 14 then AM = ?
Observe the adjoining figure and write down one pair of interior angles.
If Δ ABC ∼ Δ XYZ then complete the following brackets.
`(AB)/(XY) = /(YZ) = (AC)/`
Draw ∠ ARP= 115° and bisect it.
Draw seg AB of length 5.7 cm and bisect it.
Construct ∠ABC = 60° and bisect it
Draw Seg AB of length 9.7 cm. Take point P on it such that AP = 3.5 cm and A–P–B. Construct perpendicular to seg AB from point P.
Draw seg AB of length 4.5 cm and draw its perpendicular bisector
Point P is at a distance of 6 cm from line AB. Draw a circle of radius 4 cm passing through point P so that line AB is the tangent to the circle
