Advertisements
Advertisements
Question
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Sum
Solution
`4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
= `4/(6^3)^(-2/3) + 1/(4^4)^(-3/4) + 2/(3^5)^(-1/5)`
= `4/(6)^-2 + 1/(4)^-3 + 2/(3)^-1`
= 4 x 62 + 1 x 43 + 2 x 3
= 4 x 36 + 1 x 64 + 6
= 144 + 64 + 6
= 214
shaalaa.com
Solving Exponential Equations
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Solve for x : (49)x + 4 = 72 x (343)x + 1
Solve for x: `4^(x-1) × (0.5)^(3 - 2x) = (1/8)^-x`
Prove that : `((x^a)/(x^b))^( a + b - c ) (( x^b)/(x^c))^( b + c - a )((x^c)/(x^a))^( c + a - b)`
Evaluate the following:
`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`
Evaluate the following:
`16^(3/4) + 2(1/2)^-1 xx 3^0`
Solve for x:
1 = px
Solve for x:
p3 x p-2 = px
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
Solve for x:
22x- 1 − 9 x 2x − 2 + 1 = 0
Solve for x:
5x2 : 5x = 25 : 1