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Evaluate the Following: ( 27 ) 2 3 × 8 − 1 6 ÷ 18 − 1 2 - Mathematics

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Question

Evaluate the following:

`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`

Sum

Solution

`(27)^(2/3) xx 8^((-1)/6) ÷ 18^((-1)/2)`

= `3^(3 xx 2/3) xx (1)/(2^(3 xx 1/6)) ÷ (1/18)^(1/2)`

= `(3^2)/(2^(1/2)) xx (2 xx 3^2)^(1/2)`

= `(3^2)/(2^(1/2)) xx 2^(1/2) xx 3`

= `3^(2 + 1)`
= 33
= 27.

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Solving Exponential Equations
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Chapter 9: Indices - Exercise 9.1

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 9 Indices
Exercise 9.1 | Q 6.4
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