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Question
If 2400 = 2x x 3y x 5z, find the numerical value of x, y, z. Find the value of 2-x x 3y x 5z as fraction.
Solution
2400 = 2x x 3y x 5z
2400 = 2 x 2 x 2 x 2 x 2 x 3 x 5 x 5
∴ 2x x 3y x 5z = 25 x 31 x 52
⇒ x = 5, y = 1, z = 2
∴ 2-x x 3y x 5z = 2-5 x 31 x 52
= `(1)/(32) xx 3 xx 25`
= `(75)/(32)`.
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