Advertisements
Advertisements
Question
If 4x + 3 = 112 + 8 × 4x, find the value of (18x)3x.
Solution
4x + 3 = 112 + 8 × 4x
⇒ 4x x 43 = 112 + 8 x 4x
⇒ 64 x 4x = 112 + 8 x 4x
Let 4x = y
64y = 112 + 8y
⇒ 56y = 112
⇒ y = 2
Substituting We get,
4x = 2
⇒ 22x = 2
⇒ 2x = 1
⇒ x = `1/2`
`( 18x )^(3x) = (18/2)^( 3 xx 1/2 ) = 9^( 3 xx 1/2 ) = ( 9^(1/2))^3 = 3^3 = 27`
APPEARS IN
RELATED QUESTIONS
Solve : 8 x 22x + 4 x 2x + 1 = 1 + 2x
Solve for x : 9x+2 = 720 + 9x
Solve for x : 3(2x + 1) - 2x + 2 + 5 = 0
Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
Evaluate the following:
`(2^6 xx 5^-4 xx 3^-3 xx 4^2)/(8^3 xx 15^-3 xx 25^-1)`
Solve for x:
2x + 3 + 2x + 1 = 320
Solve for x:
22x- 1 − 9 x 2x − 2 + 1 = 0
Solve for x:
9x+4 = 32 x (27)x+1
Prove the following:
`sqrt(x^-1 y) · sqrt(y^-1 z) · sqrt(z^-1 x)` = 1
Prove the following:
`root("ab")(x^"a"/x^"b")·root("bc")(x^"b"/x^"c")·root("ca")(x^"c"/x^"a")` = 1
