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Question
Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
Sum
Solution
`[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`
= `[(- 3/2 )^2]^3 xx (3)^4 xx 1/3 xx 1/[ 3 xx 2 ]`
= `( -3/2)^6 xx (3)^2 xx 1/2`
= `3^(6 + 2 )/2^(6 + 1)`
= `3^8/2^7`
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Solving Exponential Equations
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