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Factorise: a3-22b3 - Mathematics

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Question

Factorise:

`a^3 - 2sqrt(2)b^3`

Sum

Solution

`a^3 - 2sqrt(2)b^3 = (a)^3 - (sqrt(2)b)^3`

= `(a - sqrt(2)b)[a^2 + a(sqrt(2)b) + (sqrt(2)b)^2]`  ...[Using identity, a3 – b3 = (a – b)(a2 + ab + b2)]

= `(a - sqrt(2)b)(a^2 + sqrt(2)ab + 2b^2)`

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Factorisation of Polynomials
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Chapter 2: Polynomials - Exercise 2.3 [Page 22]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 9
Chapter 2 Polynomials
Exercise 2.3 | Q 34. (ii) | Page 22
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