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Question
Factorise the following:
`8p^3 + 12/5 p^2 + 6/25 p + 1/125`
Solution
`8p^3 + 12/5 p^2 + 6/25 p + 1/125`
= `(2p)^3 + 3 xx (2p)^2 xx 1/5 + 3 xx (2p) xx (1/5)^2 + (1/5)^3`
= `(2p + 1/5)^3` ...[Using identity, (a + b)3 = a3 + b3 + 3a2b + 3ab2]
= `(2p + 1/5)(2p + 1/5)(2p + 1/5)`
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