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Question
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`1/36a^2b^2 - 16/49b^2c^2`
Sum
Solution
We have,
`1/36a^2b^2 - 16/49b^2c^2 = ((ab)/6)^2 - ((4bc)/7)^2`
= `((ab)/6 + (4bc)/7)((ab)/6 - (4bc)/7)`
= `b^2(a/6 + (4c)/7)(a/6 - (4c)/7)`
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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 235]
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