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Find the Area of the Triangle Formed by Joining the Midpoints of the Sides of the Triangle Whose Vertices Are A(2,1) B(4,3) and C(2,5) - Mathematics

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Question

Find the area of the triangle formed by joining the midpoints of the sides of the triangle whose vertices are A(2,1) B(4,3) and C(2,5)

Solution

The verticals of the triangle are A(2,1) , B (4,3) and C(2,5).

`"Coordinates of midpoint of"  AB = P (x_1,y_1)= ((2+4)/2,(1+3)/2) = (3,2)`

`"Coordinates of midpoint of " BC = Q(x_2,y_2) = ((4+2)/2,(3+5)/2) = (3,4)`

`"Coordinates of midpoint of"  AC =R (x_3,y_3) = ((2+2)/2, (1+5)/2) = (2,3)`

Now, 

`"Area of " ΔPQR =1/2 [x_2(y_2-y_3) +x_2 (y_3-y_1) +x_3 (y_1-y_2)]`

`=1/2[3(4-3)+3(3-2)+2(2-4)]`

`=1/2[3+3-4]=1` sq. unit

Hence, the area of the quadrilateral triangle is 1 sq. unit.

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Chapter 16: Coordinate Geomentry - Exercises 3

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RS Aggarwal Mathematics [English] Class 10
Chapter 16 Coordinate Geomentry
Exercises 3 | Q 6

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