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Question
Find the centroid of ΔABC whose vertices are A(-1, 0) B(5, -2) and C(8,2)
Solution
`Here , (x_1 = -1, y_1=0),(x_2 = 5, y_2 =-2) and (x_3 = 8 , y_3 =2) `
Let G (x,y) be the centroid of the Δ ABC . Then ,
`x= 1/3 (x_1 +x_2+x_3) = 1/3 (-1+5+8)=1/3(12)=4`
`y=1/3 (y_1 +y_2 +y_3) =1/3 (0-2+2) = 1/3 (0) = 0`
Hence, the centroid of ΔABC is G (4,0).
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