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Question
Find the depth of a cylindrical tank of radius 28 m, if its capacity is equal to that of a rectangular tank of size 28 m × 16 m × 11 m.
Solution
Let x be the depth of cylindrical tank.
The radius of tank r = 28 m.
Since,
The volume of cylindrical tank = volume of rectangular tank
\[\pi r^2 x = 28 \times 16 \times 11\]
\[ \Rightarrow \frac{22}{7} \times 28 \times 28 \times x = 28 \times 16 \times 11\]
`x = (28 xx 16 xx 11xx 7)/(22 xx 28 xx 28)`
` = 16/8`
`x = 2m`
Thus, the depth of cylindrical tank = 2 m.
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