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Question
Find df for f(x) = x2 + 3x and evaluate it for x = 3 and dx = 0.02
Solution
y = f(x) = x2 + 3x
dy = (2x + 3) dx
dy {when x = 3 and dx = 0.02}
= [2(3) + 3](0.0.2)
= 9(0.02)
= 0.18
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